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0.7x^2=3x^2-5.5
We move all terms to the left:
0.7x^2-(3x^2-5.5)=0
We get rid of parentheses
0.7x^2-3x^2+5.5=0
We add all the numbers together, and all the variables
-2.3x^2+5.5=0
a = -2.3; b = 0; c = +5.5;
Δ = b2-4ac
Δ = 02-4·(-2.3)·5.5
Δ = 50.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{50.6}}{2*-2.3}=\frac{0-\sqrt{50.6}}{-4.6} =-\frac{\sqrt{}}{-4.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{50.6}}{2*-2.3}=\frac{0+\sqrt{50.6}}{-4.6} =\frac{\sqrt{}}{-4.6} $
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